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Locally bounded function

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In mathematics, a function is locally bounded, if it is bounded around every point. A family of functions is locally bounded, if for any point in their domain all the functions are bounded around that point and by the same number.

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Locally bounded function

A function f defined on some topological space X with real or complex values is called locally bounded, if for any x0 in X there exists a neighborhood A of x0 such that f (A) is a bounded set, that is, for some number M>0 one has

|f(x)|\le M

for all x in A.

This definition can be extended to the case when f takes values in some metric space. Then, the inequality above needs to be replaced with

d\left(f(x), a\right)\le M

for all x in A, where d is the distance function in the metric space, and a is some point in the metric space. The choice of a does not affect the definition. Choosing a different a will at most increase the constant M for which this inequality is true.

Examples

  • The function f: RR
f(x)=\frac{1}{x^2+1}\,

is bounded, because 0≤ f (x) ≤ 1 for all x. Therefore, it is also locally bounded.

  • The function f: RR
f(x)=2x+3\,

is not bounded, as it becomes extremely large when x is large. However, it is locally bounded.

  • The function f:RR defined by
f(x)=\frac{1}{x}\,

for x ≠ 0 and taking the value 0 for x=0 is not locally bounded. In any neighborhood of 0 this function takes values of arbitrarily large magnitude.

Locally bounded family

A set (also called a family) U of functions defined on some topological space X with real or complex values is called locally bounded, if for any x0 in X there exists a neighborhood A of x0 and a positive number M such that

|f(x)|\le M

for all x in A and f in U. In other words, all the functions in the family must be locally bounded, and around each point they need to be bounded by the same constant.

This definition can also be extended to the case when the functions in the family U take values in some metric space, by again replacing the absolute value with the distance function.

Examples

  • The family of functions fn:RR
f_n(x)=\frac{x}{n}

where n = 1, 2, ... is uniformly bounded. Indeed, if x0 is a real number, one can choose the neighborhood A to be the interval (x0-1, x0+1). Then for all x in this interval and for all n≥1 one has

|f_n(x)|\le M

with M=|x0|+1.

  • The family of functions fn:RR
f_n(x)=\frac{1}{x^2+n^2}

is locally bounded. For any x0 one can choose the neighborhood A to be R itself. Then we have

|f_n(x)|\le M

with M=1. Note that the value of M does not depend on the choice of x0 or its neighborhood A. This family is then more than locally bounded, it is actually uniformly bounded .

  • The family of functions fn:RR
fn(x) = x + n

is not locally bounded. Indeed, for any x0 the values fn(x0) cannot be bounded as n tends toward infinity.

External links

11-30-2008 18:11:33
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