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Ultraparallel theorem

In hyperbolic geometry, the Ultraparallel theorem states that every pair of ultraparallel lines in the hyperbolic plane has a unique common perpendicular hyperbolic line.

Let a < b < c < d be four distinct points on the abscissa of the Cartesian plane. Let p and q be semicircles above the abscissa with diameters ab and cd respectively. Then in the upper half-plane model HP, p and q represent ultraparallel lines.

Compose the following hyperbolic motions:

x \to x-a\,
\mbox{inversion in the unit semicircle}\,.

Then a \to \infty, b \to (b-a)^{-1}, c \to (c-a)^{-1}, d \to (d-a)^{-1}.

x \to x-(b-a)^{-1}\,
x \to \left [ (c-a)^{-1} - (b-a)^{-1} \right ]^{-1} x\,

Then a stays at \infty, b \to 0, c \to 1, d \to z (say). The unique semicircle, with center at the origin, perpendicular to the one on 1z must have a radius tangent to the radius of the other. The right triangle formed by the abscissa and the perpendicular radii has hypotenuse of length \begin{matrix} \frac{1}{2} \end{matrix} (z+1). Since \begin{matrix} \frac{1}{2} \end{matrix} (z-1) is the radius of the semicircle on 1z, the common perpendicular sought has radius-square

\frac{1}{4} \left [ (z+1)^2 - (z-1)^2 \right ] = z\,.

The four hyperbolic motions that produced z above can each be inverted and applied in reverse order to the semicircle centered at the origin and of radius \sqrt{z} to yield the unique hyperbolic line perpendicular to both ultraparallels p and q.

10-26-2009 08:16:03
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